a)|x-5|=0
Suy ra:x-5=0
x=5
Vậy x=5
b)|x-4|=0
Suy ra:x-4=0
x=4
Vậy x=4
a ) \(\left|x-5\right|=0\)
\(\Rightarrow x=0+5\)
\(\Rightarrow x=5\)
b ) \(\left|x-4\right|=0\)
\(\Rightarrow x=0+4\)
\(\Rightarrow x=4\)
Ix - 5I = 0
=> x - 5 = 0
=> x = 5
Ix - 4I = 0
=> x - 4 = 0
=> x = 4
a) | x-5 | = 0
=> x-5 = 0
=> x= 0+5
=> x= 5
Vậy x = 5
b) | x-4 | = 0
=> x-4 = 0
=> x = 0+4
=> x= 4
Vậy x = 4
a) \(\left|x-5\right|=0\)
\(\Rightarrow x-5=0\)
\(x=0+5\)
\(x=5\)
Vậy \(x=5\)
b) \(\left|x-4\right|=0\)
\(\Rightarrow x-4=0\)
\(x=0+4\)
\(x=4\)
Vậy \(x=4\)