Question

1.

a.\(\left|2x+4\right|+\left|4x+8\right|=0\)

b.\(\left|x-5\right|+\left|x-7\right|=0\)

c.\(\left|x+8\right|-\left|2x+2\right|=0\)

Answer 1

a , x = -2

b, x\(\in\varnothing\)

c, x = 6

Answer 2

a, Ta có:

\(\left|2x+4\right|+\left|4x+8\right|\ge0\)

Để \(\left|2x+4\right|+\left|4x+8\right|=0\) thì:

\(\left\{{}\begin{matrix}\left|2x+4\right|=0\\\left|4x+8\right|=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-2\\x=-2\end{matrix}\right.\Rightarrow x=-2\)

Vậy...........

b, Ta có:

\(\left|x-5\right|+\left|x-7\right|\ge0\)

Để \(\left|x-5\right|+\left|x-7\right|=0\) thì:

\(\left\{{}\begin{matrix}\left|x-5\right|=0\\\left|x-7\right|=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=5\\x=7\end{matrix}\right.\Rightarrow x\in\varnothing\)

Vậy...........

c,\(\left|x+8\right|-\left|2x+2\right|=0\)

\(\Rightarrow\left|x+8\right|=\left|2x+2\right|\)

\(\Rightarrow\left\{{}\begin{matrix}x+8=2x+2\\x+8=-2x-2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}-x=-6\\3x=-10\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=6\\x=-\dfrac{10}{3}\end{matrix}\right.\)

Vậy...........

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