Question

Tìm x

a) \(\left(-2\right)^5+7.\left(x-8\right)=-167+8x\)

b) \(\left(7-3x\right)\left(4x+4\right)=0\)

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Answer 1

a)

(- 2)⁵ + 7(x - 8) = - 167 + 8x

32 + 7x - 56 + 167 = 8x

8x - 7x = 143

x = 143

b)

(7 - 3x)(4x + 4) = 0

4(x + 1)(7 - 3x) = 0

\(\left[\begin{matrix}x+1=0\\7-3x=0\end{matrix}\right.\)

\(\left[\begin{matrix}x=-1\\3x=7\end{matrix}\right.\)

\(\left[\begin{matrix}x=-1\\x=\frac{7}{3}\end{matrix}\right.\)

Answer 2

a) 32+ 7x-56 = -167 +8x
7x-8x = -32 +56 -167
-x = -143
x = 143
b) 7-3x = 0 hoặc 4x+4=0
1)7-3x= 0
3x= 7
x= 7/3
2)4x+4 = 0
4x = -4
x = -1

Answer 3

Phương An