Question

A = \(\dfrac{x-\sqrt{x}}{x+\sqrt{x}+1}-\dfrac{2x+\sqrt{x}}{\sqrt{x}}+\dfrac{2\left(x-1\right)}{\sqrt{x}-1}\)

a) Rút gọn A

b) Tìm x để B = \(\dfrac{2\sqrt{x}}{A}\)nguyên.

@Ace Legona@nguyen van tuanAki Tsuki

Answer 1

Chỉ cần lm p b thôi ha

Answer 2

@nguyen van tuan

A = \(\dfrac{x-\sqrt{x}}{x+\sqrt{x}+1}-\dfrac{2x+\sqrt{x}}{\sqrt{x}}+\dfrac{2\left(x-1\right)}{\sqrt{x}-1}\)

A = \(\dfrac{x-\sqrt{x}}{x+\sqrt{x}+1}-\dfrac{\sqrt{x}\left(2\sqrt{x}+1\right)}{\sqrt{x}}+\dfrac{2\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}{\sqrt{x}-1}\)

A = \(\dfrac{x-\sqrt{x}}{x+\sqrt{x}+1}-2\sqrt{x}-1+2\sqrt{x}+2\)

A = \(\dfrac{x-\sqrt{x}}{x+\sqrt{x}+1}+1=\dfrac{x-\sqrt{x}+x+\sqrt{x}+1}{x+\sqrt{x}+1}=\dfrac{2x+1}{x+\sqrt{x}+1}\)