Question

a) 5/2x + 6 và 3/x² - 9
b) 2x/x² - 8x + 16 và x/3x² - 12x
XIN CẢM ƠN

Answer 1

\(a,\dfrac{5}{2x+6}=\dfrac{5\left(x-3\right)}{2\left(x+3\right)\left(x-3\right)};\dfrac{3}{x^2-9}=\dfrac{6}{2\left(x-3\right)\left(x+3\right)}\\ b,\dfrac{2x}{x^2-8x+16}=\dfrac{6x}{3\left(x-4\right)^2};\dfrac{x}{3x^2-12x}=\dfrac{1}{3x-12}=\dfrac{x-4}{3\left(x-4\right)^2}\)

Answer 2

a)\(\dfrac{5}{2x+6}=\dfrac{5}{2\left(x+3\right)}=\dfrac{5\left(x-3\right)}{2\left(x+3\right)\left(x-3\right)}=\dfrac{5x-15}{2\left(x+3\right)\left(x-3\right)}\\ \dfrac{3}{x^2-9}=\dfrac{3}{\left(x-3\right)\left(x+3\right)}=\dfrac{6}{2\left(x-3\right)\left(x+3\right)}\)