a) (\(2\sqrt{3}+\sqrt{5}\)).\(\sqrt{3}-\sqrt{60}\) = \(2\sqrt{3}^2+\sqrt{5}.\sqrt{3}-2\sqrt{15}\)
= \(6+\left(\sqrt{15}-2\sqrt{15}\right)\)= 6\(-\sqrt{15}\)
b) \(\left(5\sqrt{2}+2\sqrt{5}\right)\sqrt{5}-\sqrt{250}\) = \(2\sqrt{5}^2+\left(5\sqrt{2}.\sqrt{5}-\sqrt{250}\right)\)
= \(2.5+\left(\sqrt{250}-\sqrt{250}\right)\) = 10
"√"= can 2
ai chang biet
(≥6)
van de de bat lam gi?
=> do hoi