\(\left(a-2009\right)^2+\left(b+2010\right)^2=0\)
Ta có:
\(\left\{{}\begin{matrix}\left(a-2009\right)^2\ge0\\\left(b+2010\right)^2\ge0\end{matrix}\right.\forall a,b.\)
\(\Rightarrow\left(a-2009\right)^2+\left(b+2010\right)^2\ge0\) \(\forall a,b\)
\(\Rightarrow\left(a-2009\right)^2+\left(b+2010\right)^2=0\)
\(\Rightarrow\left\{{}\begin{matrix}\left(a-2009\right)^2=0\\\left(b+2010\right)^2=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a-2009=0\\b+2010=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0+2009\\b=0-2010\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}a=2009\\b=-2010\end{matrix}\right.\)
Vậy \(\left(a;b\right)\in\left\{2009;-2010\right\}.\)
Chúc bạn học tốt!
