8\(x^2\)+ 4xy - 2ax - ay
=4x(2x + y) - a(2x - y)
=(2x + y)(4x - a)
Dễ mà bạn!!!
\(8x^2+4xy-2ax-ay\)
= \(\left(8x^2+4xy\right)-\left(2ax+ay\right)\)
= \(4x\left(2x+y\right)-a\left(2x+y\right)\)
= \(\left(2x+y\right)\left(4x-a\right)\)
\(8x^2+4xy-2ax-ay\\ =4x\left(2x+y\right)-a\left(2x+y\right)\\ =\left(2x+y\right)\left(4x-a\right)\)