Question

7x(x-4)-(7x+3)(2X^2+4)

Answer 1

=7x^2-28x-14x^3-28x-6x^2-12

=-14x^3+x^2-56x-12

Answer 2

`7x . (x-4) - ( 7x + 3 ) . ( 2x^2 + 4 )`
`= 7x^2 - 28x - ( 14x^3 + 28x + 6x^2 + 12 )`
`= 7x^2 - 28x - 14x^3 - 28x - 6x^2 - 12`
`= -14x^3 + x^2 - 56x - 12`