Question

6n+8 chia hết cho 2n+1 n=bnhieeu

 

Answer 1

\(\dfrac{6n+8}{2n+1}=\dfrac{\left(6n+3\right)+5}{2n+1}=3+\dfrac{5}{2n+1}\)
Do đó để \(\left(6n+8\right)⋮\left(2n+1\right)\) thì \(2n+1\inƯ\left(5\right)=\left\{1;5\right\}\)
Ta có bảng sau:

\(2n+1\)	\(1\)	\(5\)
\(2n\)	\(0\)	\(4\)
\(n\)	\(0\)	\(2\)

Vậy để \(\left(6n+8\right)⋮\left(2n+1\right)\) thì \(n\in\left\{0;2\right\}\)
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