\(\frac{6}{2.4}+\frac{6}{4.6}+...+\frac{6}{98.100}\)
= \(\frac{6}{2}.\left(\frac{2}{2.4}+\frac{2}{4.6}+...+\frac{2}{98.100}\right)\)
= \(3.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{98}-\frac{1}{100}\right)\)
= \(3.\left(\frac{1}{2}-\frac{1}{100}\right)\)
= \(3.\frac{49}{100}\)
= \(\frac{147}{100}\)