Question

6) Làm tính chia

a) 14𝑥3𝑦∶10𝑥2

b) (𝑥3−27)∶(3−𝑥)

c) 8𝑥3𝑦3𝑧∶6𝑥𝑦3

d) (𝑥2−9𝑦2+4𝑥+4)∶(𝑥+3𝑦+2)

Answer 1

a) \(14x^3y:10x^2=\dfrac{7}{5}xy\)

b) \(\left(x^3-27\right):\left(3-x\right)\)

\(=\left(x-3\right)\left(x^2+3x+9\right):\left(3-x\right)\)

\(=-\left(3-x\right)\left(x^2+3x+9\right):\left(3-x\right)\)

\(=-\left(x^2+3x+9\right)\)

\(=-x^2-3x-9\)

Answer 2

bạn nào giải giúp mình nha

Answer 3

c) \(8x^3y^3z:6xy^3=\dfrac{4}{3}x^2z\)

d) \(\left(x^2-9y^2+4x+4\right):\left(x^2+3y+2\right)\)

\(=\left[\left(x+2\right)^2-\left(3y\right)^2\right]:\left(x^2+3y+2\right)\)

\(=\left(x+3y+2\right)\left(x-3y+2\right):\left(x^2+3y+2\right)\)

\(=x-3y+2\)