\(\Leftrightarrow\left(2x+3;-2y+5\right)\in\left\{\left(1;-7\right);\left(-7;1\right);\left(-1;7\right);\left(7;-1\right)\right\}\)
hay \(\left(x,y\right)\in\left\{\left(-1;6\right);\left(-5;2\right);\left(-2;-1\right);\left(2;2\right)\right\}\)
thực hiện phép tính
a.\(-2xy^2.\left(x^3y-2x^2y^2+5xy^3\right)\)
b.\(\left(-2x\right).\left(x^3-3x^2-x+1\right)\)
c.3x\(^2\left(2x^3-x+5\right)\)
d.\(\left(-10x^3+\frac{2}{5}y-\frac{1}{3}z\right).\left(-\frac{1}{2}xy\right)\)
e.\(\left(3x^2y-6xy+9x\right).\left(-\frac{4}{3}xy\right)\)
f.\(\left(4xy+3y-5x\right).x^2y\)
Cho \(A=\dfrac{\left|2x-3\right|+\left|6y-7\right|}{\left|9-6x\right|+\left|18y-21\right|}-\dfrac{\left(x-2\right)^2+\left(2y-4\right)^2}{\left(3x-6\right)^2+\left(12-6y\right)^2}\). Rút gọn A
Thu gọn biểu thức sau rồi cho biết hệ số phần biến và bậc
\(\left(-z^2y^4\right)^2+\left(-\dfrac{2}{5}z^2y\right).\left(5x^2y^7\right).\left(\dfrac{4}{5}x^2y^5\right)^0-\left(\dfrac{9}{10}z^5y^7-z^4y^8\right)\)
CÁC BẠN GIÚP MK NHÉ MK CẦN GẤP LẮM!!!!!!!!!!!!!
Bài 1: Thu gọn
a) \(\frac{1}{5}x^4y^3-3x^4y^3\)
b) \(5x^2y^5-\frac{1}{4}x^2y^5\)
c) \(\frac{1}{7}x^2y^3.\left(-\frac{14}{3}xy^2\right)-\frac{1}{2}xy.\left(x^2y^{\text{4}}\right)\)
d) \(\left(3xy\right)^2.\left(-\frac{1}{2}x^3y^2\right)\)
e) \(-\frac{1}{4}xy^2+\frac{2}{5}x^2y+\frac{1}{2}xy^2-x^2y\)
f) \(\frac{1}{2}x^4y.\left(-\frac{2}{3}x^3y^2\right)-\frac{1}{3}x^7y^3\)
g) \(\frac{1}{2}x^2y.\left(-10x^3yz^2\right).\frac{1}{4}x^5y^3z\)
h) \(4.\left(-\frac{1}{2}x\right)^2-\frac{3}{2}x.\left(-x\right)+\frac{1}{3}x^2\)
i) \(1\frac{2}{3}x^3y.\left(\frac{-1}{2}xy^2\right)^2-\frac{5}{4}.\frac{8}{15}x^3y.\left(-\frac{1}{2}xy^2\right)^2\)
k) \(-\frac{3}{2}xy^2.\left(\frac{3}{4}x^2y\right)^2-\frac{3}{5}xy.\left(-\frac{1}{3}x^4y^3\right)+\left(-x^2y\right)^2.\left(xy\right)^2\)
n) \(-2\frac{1}{5}xy.\left(-5x\right)^2+\frac{3}{4}y.\frac{2}{3}\left(-x^3\right)-\frac{1}{9}.\left(-x\right)^3.\frac{1}{3}y\)
m) \(\left(-\frac{1}{3}xy^2\right)^2.\left(3x^2y\right)^3.\left(-\frac{5}{2}xy^2z^3\right)^{^2}\)
p) \(-2y.\left|2\right|x^4y^5.\left|-\frac{3}{4}\right|x^3y^2z\)
Tìm đa thức M , biết :
a) \(M-\left(\frac{1}{2}x^2y-5xy^2+x^3-y^3\right)=\frac{3}{4}xy^2-2x^2y+\)\(2y^3-\frac{1}{3}x^3\)
b)\(\left(-\frac{1}{3}x^3y^3+5x^2y^2-\frac{5}{2}xy\right)-M=xy-\frac{1}{6}x^3y^3-3x^2y^2\)
c)\(\left(\frac{2}{7}xy^4-5x^5+7x^2y^3-3\right)+M=0\)
thực hiện phép tính
a.\(5x^2-3x\left(x+2\right)\)
b.\(3x\left(x-5\right)-5x\left(x+7\right)\)
c.\(3x^2y.\left(2x^2-y\right)-2x^2.\left(2x^2y-y^2\right)\)
d.\(3x^2.\left(2y-1\right)-\left[2x^2.\left(5y-3\right)-2x.\left(x-1\right)\right]\)
e.\(4x\left(x^3-4x^2\right)+2x\left(2x^3-x^2+7x\right)\)
f.\(25x-4\left(3x-1\right)+7x\left(5-2x^2\right)\)
\(C=2x-2y+13x^3y^2\left(x-y\right)+15\left(y^2x-x^2y\right)+\left(\dfrac{2015}{2016}\right)^0bitx-y=0\)
mong các bạn giúp minh
Bài 1: Chứng minh rằng biểu thức sau không phụ thuộc vào giá trị của biến:
M= \(1-y^2-3.\left(2y-y^2\right)-\left(7-6y+2y^2\right)\)
GIÚP MIK NHA!!! MIK ĐAG CẦN GẤP
bài 1 tính
\(A=\frac{a+b}{b+c}\) biết \(\frac{b}{a}=2;\frac{c}{b}=3\)
bài 2 tìm x
a) \(\frac{72-x}{7}=\frac{x-40}{9}\)
b) \(\frac{x+4}{20}=\frac{5}{x+4}\)
bài 3 tìm x,y
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
bài 8 tìm x,y,z
a) x:y:z=3:4:5 và 2x2+2y2-3z2=-100
b)\(\frac{x}{y+z+1}=\frac{y}{x+z+1}=\frac{z}{x+y-2}=x+y+z\)
c) \(\left|x-3\right|+\left|y+5\right|+\left|x+y+z\right|=0\)
d) \(\left|2x-5\right|+\left|2y-z\right|+\left|4z-2\right|=0\)
