a) Viết PTHH chứ bn
\(Fe+2HCl\rightarrow FeCl_2+H_2\)
b) Theo ĐLBTKL, ta có:
\(m_{Fe}+m_{HCl}=m_{FeCl_2}+m_{H_2}\)
c) Theo DDLBTKL, ta có:
\(m_{Fe}+m_{HCl}=m_{FeCl_2}+m_{H_2}\)
\(5,6+7,3=12,7+m_{H_2}\)
\(\Rightarrow m_{H_2}=0,2\left(g\right)\)
\(\Rightarrow n_{H_2}=\frac{m_{H_2}}{M_{H_2}}=\frac{0,2}{2}=0,1\left(mol\right)\)
\(\Rightarrow V_{H_2}=n_{H_2}.22,4=0,1.22,4=2,24\left(ml\right)\)