4x^2-2x=0
2x(2x-1)=0
2x-1=0
2x=1
x=1/2
Vậy x=1/2
4x-2x=0
2x(2x-1)=0
suy ra 2x=0 hoặc 2x-1=0
suy ra x=0 hoặc x=1/2
Ta có: \(4x^2-2x=0\)
\(\Leftrightarrow2x\left(2x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\end{matrix}\right.\)