Question

4.(3𝑥^2−7𝑥+2 )=0

Answer 1

\(3x^2-7x+2=0\)

\(\Leftrightarrow3x^2-6x-x+2=0\)

\(\Leftrightarrow3x\left(x-2\right)-\left(x-2\right)=0\)

\(\Leftrightarrow\left(3x-2\right)\left(x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-1=0\\x-2=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=2\end{matrix}\right.\)

Answer 2

ĐK: x > 0 
x = 7/3 hoặc x = -2
Vậy S = \(\left\{\dfrac{7}{3}\right\}\)

Answer 3

Ta có: \(3x^2-7x+2=0\)

\(\Leftrightarrow\left(x-2\right)\left(3x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{3}\end{matrix}\right.\)