Bài 4: Phương trình tích
Các câu hỏi tương tự
22 tháng 3 2021 lúc 20:54
Giải phương trình:
a) \(\dfrac{x^2-x-6}{x-3}=0\)
b) \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)
c) \(\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
d) \(\dfrac{x+5}{x-1}=\dfrac{x+1}{x-3}-\dfrac{8}{x^2-4x+3}\)
e) \(\dfrac{x+1}{x-2}-\dfrac{5}{x+2}=\dfrac{12}{x^2-4}+1\)Thể loại truyện
giải các phương trình
a) (3x-2)(3x-1) = (3x+1)2
b) (4x-1)(x+1) = (2x-3)2
c) (5x+1)2 = (7x-3)(7x+2)
d) (4-3x)(4+3x)=(9x-3)(1-x)
e) x(x+1)(x+2)(x+3)=24
g) (7x - 2)2= (7x-3)(7x+2)
Bài 1: giải các pt sau:
1,(x-1)^2-(x+1)^2=2(x+3)
2,(2x-1)^2-(2x+1)^2=4(x-3)
3,(2x+3)^2-(2x+3).(2x-4)=-(x-2)^2
4,8x^3-(x+1)^3=3x-3
5,(3x-2).(9x^2+6x+4)-(3x+1).(9x^2-3x+1)=(2x+1).(2x-1)-4x(x-3)
1|(X+2)^2-(x-1)^2=(3x-1).(3x+1)
5 tháng 2 2021 lúc 20:04
GPT sau:
a) ( x-1)(5x+3)= (3x - 8 )(x-1)
b) 3x ( 25x + 15 )- 35 ( 5x+3) = 0
c) (2-3x ) ( x-11)=(3x-2)(2- 5x)
Giups mk vs thank cacs bn
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) 0
c) 2x(x – 3) + 5(x – 3) 0 d) (3x – 1)(x2 + 2) (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) x2 + 4x + 4 f) x(2x – 7) – 4x + 14 0
g) 3x – 15 2x(x – 5) h) (2x + 1)(3x – 2) (5x – 8)(2x + 1)
i) 0,5x(x – 3) (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) (x – 12)(2x2 + 1)
k) x(2x – 9) 3x(x – 5) l) (x – 1)(5x + 3) (3...
Đọc tiếp
Bài 1: Giải các phương trình tích sau:
2. a) (3x + 2)(x2 –1) = (9x2 – 4)(x + 1) b)x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0
c) 2x(x – 3) + 5(x – 3) = 0 d) (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)
e) (x + 2)(3 – 4x) = x2 + 4x + 4 f) x(2x – 7) – 4x + 14 = 0
g) 3x – 15 = 2x(x – 5) h) (2x + 1)(3x – 2) = (5x – 8)(2x + 1)
i) 0,5x(x – 3) = (x – 3)(1,5x – 1) j) (2x2 + 1)(4x – 3) = (x – 12)(2x2 + 1)
k) x(2x – 9) = 3x(x – 5) l) (x – 1)(5x + 3) = (3x – 8)(x – 1)
Giải phương trình :
a)(2x-5)^3-(3x-4)^x+(x+1)^3=0
b)(x-1)^3+(2x-3)^3+(3x-5)^3 - 3(x-1)(2x-3)(3x-5) = 0
c)(x^2+3x-4)^3 + (3x^2+7x+4)^3 = (4x^2+10x)^3
1/(2x-1)(3x+2)(5-x)=0
2/(2x+5)(x-4)=(x-5)(4-x)
3/16x^2-8x+1=4(x+3)(4x-1)
4/27x^2(x+3)-12(×^2+3x)=0
5/2(9x^2+6x+1)=(3x+1)(x-2)
6/(2x-1)^2=49
12/(1-9x22)=(1-3x)/(1+3x) - (1+3x)/(x+1)
a)(x-1)(x^2+5x-2)-x^3+1=0
b)5(x^2+3x)-9(3x+3)=x^2-36