Question

(3x + 2)(4x - 5) = 0

Answer 1

\(|^{3x+2=0}_{4x-5=0}\Rightarrow|^{x=-\dfrac{2}{3}}_{x=\dfrac{5}{4}}\)

Answer 2

\(\left(3x+2\right)\left(4x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x+2=0\\4x-5=0\end{matrix}\right.\Leftrightarrow}\left[{}\begin{matrix}2=\dfrac{-2}{3}\\x=\dfrac{5}{4}\end{matrix}\right.\)

Answer 3

\(\left(3x+2\right)\left(4x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x+2=0\\4x-5=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=\dfrac{5}{4}\end{matrix}\right.\)

Vậy...

Answer 4

(3x + 2)(4x -5) =0

<=>\(\left[{}\begin{matrix}3x+2=0\\4x-5=0\end{matrix}\right.\)=>\(\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=\dfrac{5}{4}\end{matrix}\right.\)

vậy pt có tập nghiệm {-2/3;5/4}