a) \(3x-2\left(2x-1\right)=1\frac{1}{3}\)
\(\Leftrightarrow3x-4x+2=1\frac{1}{3}\)
\(\Leftrightarrow-x=-\frac{2}{3}\)
\(\Leftrightarrow x=\frac{2}{3}\)
Vậy ....
b) \(\frac{x+4}{20}=\frac{5}{x+4}\)
\(\Leftrightarrow\left(x+4\right)^2=100\)
\(\Leftrightarrow\left[{}\begin{matrix}x+4=10\\x+4=-10\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-14\end{matrix}\right.\)
Vậy \(x\in\left\{6;-14\right\}\)
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