\(A=\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5+\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
Tính: a ) \(-3\frac{3}{4}+\frac{-10}{25}+\frac{-6}{12}\)
b) \(-0,6-\frac{-4}{9}-\frac{16}{15}\)
c ) \(\frac{7}{12}-\left(-\frac{1}{15}\right)-\frac{5}{6}+\frac{2}{3}+\left(-\frac{1}{5}\right)\)
BT3; Tính
a,\(\frac{1}{2}\)-(\(\frac{1}{3}\)+\(\frac{1}{10}\))
b,\(\frac{1}{12}\)-(-\(\frac{1}{6}\)-\(\frac{1}{4}\))
c,\(\frac{2}{5}\)+(-\(\frac{4}{3}\))+(-\(\frac{1}{2}\))
tìm x ∈ N, biết:
\(\frac{1}{4}\)+ \(\frac{8}{9}\)≤ \(\frac{x}{36}\)< 1- (\(\frac{3}{8}\)- \(\frac{5}{6}\))
Tìm x biết :
1) \(\frac{x+1}{15}\)+ \(\frac{x+2}{14}\)=\(\frac{x+3}{13}\)+\(\frac{x+4}{12}\)
2) \(\frac{x+1}{2012}\)+\(\frac{x+2}{2011}\)+\(\frac{x+3}{2010}\)=\(\frac{x+4}{2009}\)+\(\frac{x+5}{2008}\)+\(\frac{x+6}{2007}\)
3)\(\frac{x-2}{2013}\)+\(\frac{x-1}{2014}\)=\(\frac{x-3}{2012}\)+\(\frac{x-4}{2011}\)
4)\(\frac{x-3}{20}\)+\(\frac{x-2}{21}\)=\(\frac{x-1}{22}\)+\(\frac{x}{23}\)
5)\(\frac{x+1}{20}\)+\(\frac{x+2}{19}\)+\(\frac{x+3}{18}\)= -3
6) \(\frac{x-1}{91}\)+\(\frac{x-2}{90}\)+\(\frac{x-3}{89}\)+\(\frac{x-4}{88}\)= 5
Ai giúp mình vs...Cả đống bài tập mà chẳng biết làm gì hết
Ai làm giúp mình sẽ tick nhé
bài 1: Tính nhanh:
A= \(\frac{1}{3}\)- \(\frac{3}{4}\)- (\(\frac{-3}{5}\))+ \(\frac{1}{72}\)- \(\frac{2}{9}\)- \(\frac{1}{36}\)+ \(\frac{1}{15}\)
B= (3+ \(\frac{1}{2}\)- \(\frac{2}{3}\)) - (2- \(\frac{2}{3}\)+ \(\frac{5}{2}\))- (5- \(\frac{5}{2}\)+ \(\frac{4}{3}\))
bài 2: tìm các số nguyên x,y; biết:
\(\frac{x}{6}\)- \(\frac{1}{y}\)= \(\frac{1}{2}\)
bài 3:tính :
S1= \(\frac{3}{1.4}\)+ \(\frac{6}{4.10}\)+ \(\frac{9}{10.19}\)+ \(\frac{12}{19.31}\)+ \(\frac{15}{31.46}\)
S2= \(\frac{3}{1.5}\)+ \(\frac{3}{5.9}\)+ \(\frac{3}{9.13}\)+....+ \(\frac{3}{89.93}\)
MỌI NGƯỜI GIẢI NHANH GIÚP MÌNH VỚI. MÌNH ĐANG CẦN GẤP TRONG TRƯA NAY
tìm x , biết
a) 17/6- x( x-7/6)= 7/4
b) 3/35 - ( 3/5-x)= 2/7
tìm x thuộc Z , biết
3/4-5/6 < x/12 < 1 -( 2/3-1/4)
tìm x biết
a ) 2x-3=x + 1/2
b) 4x- ( x+ 1/2) = 2x - ( 1/2 - 5 )
1)Tính nhanh giá trị biểu thức
A=\(\frac{1}{3}-\frac{3}{4}-\left(\frac{-3}{5}\right)+\frac{1}{64}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
B=\(\left(\frac{-1}{2}\right)-\left(\frac{-3}{5}\right)+\left(\frac{-1}{9}\right)+\frac{1}{131}-\left(\frac{-2}{7}\right)+\frac{4}{35}-\frac{7}{18}\)
B=\(\frac{1}{3}-\frac{3}{4}-\left(-0,6\right)+\frac{1}{64}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
C=\(\frac{1}{3}-\frac{3}{5}+\frac{5}{7}-\frac{7}{9}+\frac{9}{11}-\frac{11}{13}+\frac{13}{15}+\frac{11}{15}+\frac{11}{13}-\frac{9}{11}+\frac{7}{9}-\frac{5}{7}+0,6-\frac{1}{3}\)
D=\(\frac{1}{99}-\frac{1}{99.98}-\frac{1}{98.97}.....-\frac{1}{3.2}-\frac{1}{2.1}\)