Question

(3x-1)^2-(x+5)^2=0

Answer 1

`(3x-1)^2-(x+5)^2=0`

`<=>(3x-1-x-5)(3x-1+x+5)=0`

`<=>(2x-6)(4x+4)=0`

`<=>(x-3)(x+1)=0`

`<=>[(x=3),(x=-1):}`

Answer 2

<=> 9x^2 - 6x + 1 - x^2 - 10x - 25 = 0

<=> 8x^2 -16x - 24 =0

<=> 8x^2 - 24x + 8x - 24 =0

<=> 8[x(x-3) + (x-3)] = 0 <=> x-3 = 0  => x=3

                                              x+1 = 0      x=-1