Question

(3x -1)(2x-3)(2x-3)(x+5)=0

(x+1)(x+4)=(2-x)(x+2)

Answer 1

cau 1

(3x-1)(2x-3)(2x-3)(x+5)=0

\(\Leftrightarrow\)(2x-3)[(3x-1)*(x+5)]=0

\(\Leftrightarrow\)(2x-3)(3x²+15x-x-5)=0

\(\Leftrightarrow\)(2x-3)[3x(x+5)-(x+5)]=0

\(\Leftrightarrow\)(2x-3)(x+5)(3x-1)=0

\(\Leftrightarrow\)2x-3=0 hoac x+5=0 hoac 3x-1=0

\(\Leftrightarrow\)x=3/2\(\Leftrightarrow\)x=-5\(\Leftrightarrow\)x=1/3

vay s={3/2,-5,1/3}

cau 2

(x+1)(x+4)=(2-x)(x+2)

\(\Leftrightarrow\)x²+4x+x+4=4-x²

^{\(\Leftrightarrow\)}x²+4x+x+4-4+x²=0

\(\Leftrightarrow\)2x²+5x=0

\(\Leftrightarrow\)x(2x+5)=0

\(\Leftrightarrow\)x=0 hoac 2x+5=0

\(\Leftrightarrow\)x=0\(\Leftrightarrow\)x=-5/2

vay s={0,-5/2}