\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}\)
\(\dfrac{1}{4}:x=-\dfrac{7}{20}\)
\(x=\dfrac{1}{4}:-\dfrac{7}{20}\)
\(x=-\dfrac{5}{7}\)
\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Rightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}\)
\(\Rightarrow\dfrac{1}{4}:x=\dfrac{-7}{20}\)
\(\Rightarrow x=\dfrac{1}{4}:\dfrac{-7}{20}\)
\(\Rightarrow x=\dfrac{-5}{7}\)
Vậy \(x=-\dfrac{5}{7}.\)
Giải:
\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Rightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}\)
\(\Rightarrow\dfrac{1}{4}:x=-\dfrac{7}{20}\)
\(\Leftrightarrow x=\dfrac{1}{4}:\dfrac{-7}{20}=\dfrac{1}{4}.\dfrac{-20}{7}=\dfrac{-5}{7}\)
Vậy \(x=\dfrac{-5}{7}\)
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\(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
\(\Leftrightarrow\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{1}{4}:x=\dfrac{-7}{20}\)
\(\Leftrightarrow x=\dfrac{1}{4}:\dfrac{-7}{20}\)
\(\Leftrightarrow x=\dfrac{5}{-7}\)
Ta có: \(\dfrac{3}{4}+\dfrac{1}{4}:x=\dfrac{2}{5}\)
=>\(\dfrac{1}{4}:x=\dfrac{2}{5}-\dfrac{3}{4}\)
=>\(\dfrac{1}{4}:x=-\dfrac{7}{20}\)
=>\(x=\dfrac{1}{4}:\left(-\dfrac{7}{20}\right)\)
=>\(x=-\dfrac{5}{7}\)