33x :11x =81
↔\(\frac{33^x}{11^x}\)=81
↔(\(\frac{33}{11}\))x=81
↔3x=81
→x=4
\(33^x:11^x=81\)
\(=>\left(33:11\right)^x=81\)
\(3^x=81\)
\(3^x=3^4\)
\(=>x=4\)
Vậy x = 4
\(33^x:11^x=81\)
\(\Rightarrow\left(33:11\right)^x=81\)
\(\Rightarrow3^x=81\)
\(\Rightarrow x=4\)
Vậy : \(x=4\)
33^x : 11^x=81
(33:11)^x=81
3^x=3^4
=>x=4