Question

\(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)

Answer 1

\(3+2^{x-1}=24-\left[4^2-\cdot\left(3\right)\right]\)

\(\Rightarrow3+2^{x-1}=24-\left(13\right)\)

\(\Rightarrow3+2^{x-1}=11\)

=> 2^x-1=8

Mà : \(8=2^3\)

\(\Rightarrow2^{x-1}=2^3\)

\(\Rightarrow x-1=3\)

\(\Rightarrow x=4\)

Answer 2

\(3+2^{x-1}=24-\left(4^2-\left(2^2-1\right)\right)\)

\(2^{x-1}=24-3-\left(16-4+1\right)\)

\(2^{x-1}=21-13\)

\(2^{x-1}=8\)

\(2^{x-1}=2^3\)

\(x-1=3\)

x = 3 + 1

x = 4

Answer 3

\(3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]\)

\(\Rightarrow3+2^{x-1}=24-\left(16-3\right)\)

\(\Rightarrow3+2^{x-1}=24-13\)

\(\Rightarrow3+2^{x-1}=11\)

\(\Rightarrow2^{x-1}=8\)

\(\Rightarrow2^{x-1}=2^3\)

\(\Rightarrow x-1=3\)

\(\Rightarrow x=4\)

Vậy x = 4