Question

( 3\(^{17}\) . 81\(^{11}\) ) : ( 27\(^{10}\) . 9\(^{15}\) )

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Answer 1

\(\dfrac{3^{17}.81^{11}}{27^{10}.9^{15}}=\dfrac{3^{17}.\left(3^4\right)^{11}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\dfrac{3^{17}.3^{44}}{3^{30}.3^{30}}=\dfrac{3^{61}}{3^{60}}=3\)

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Answer 2

\(\dfrac{3^{17}.81^{11}}{27^{10}.9^{15}}=\dfrac{3^{17}.\left(3^4\right)^{11}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\dfrac{3^{17}.3^{44}}{3^{30}.3^{30}}=\dfrac{3^{61}}{3^{60}}=3\)