Ta có:
\(VT=\left(3sinx+4cosx\right)^2\le\left(3^2+4^2\right)\left(sin^2x+cos^2x\right)=25\)
\(VP=25+\left|5sinx-3\right|\ge25\)
\(\Rightarrow VT\le VP\)
Dấu "=" xảy ra khi và chỉ khi:
\(\left\{{}\begin{matrix}\frac{sinx}{3}=\frac{cosx}{4}\\5sinx=3\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}sinx=\frac{3}{5}\\cosx=\frac{4}{5}\end{matrix}\right.\) \(\Rightarrow x=...\)