3 - 4x + 24 + 6x = x + 27 + 3x
⇔ 27 + 2x = 4x + 27
⇔ 2x = 0
⇔ x = 0
3-4x+24+6x=x+27+3x
3+24-27=4x-6x+x+3x
0=2x
<=>2x=0
=> x=0
Ta có: \(3-4x+24+6x=x+27+3x\)
\(\Leftrightarrow2x+27=4x+27\)
\(\Leftrightarrow2x+27-4x-27=0\)
\(\Leftrightarrow-2x=0\)
\(\Leftrightarrow x=0\)
Vậy: S={0}