Question

2x.(x - \(\frac{1}{7}\)) = 0

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Answer 1

\(2x\left(x-\frac{1}{7}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2x=0\\x-\frac{1}{7}=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\frac{1}{7}\end{matrix}\right.\)

Vậy x = \(\left\{0;\frac{1}{7}\right\}\)

Answer 2

\(2x.\left(x-\frac{1}{7}\right)=0\)

\(\left\{{}\begin{matrix}2x=0\\x-\frac{1}{7}=0\end{matrix}\right.\) => \(\left\{{}\begin{matrix}x=0:2\\x=0+\frac{1}{7}\end{matrix}\right.\)

=> \(\left\{{}\begin{matrix}x=0\\x=\frac{1}{7}\end{matrix}\right.\)

Vậy x ∈ \(\left\{0;\frac{1}{7}\right\}\)

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Answer 3

2x.(x - \(\frac{1}{7}\)) = 0

TH1:

2x = 0

x = 0 : 2

⇒x = 0

TH2:

x - \(\frac{1}{7}\) = 0

x = 0 + \(\frac{1}{7}\)

⇒x = \(\frac{1}{7}\)

Vậy x ∈ {0; \(\frac{1}{7}\)}