\(\Leftrightarrow\left[{}\begin{matrix}2x+5=3\\-2x-5=3\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}2x=-2\\-2x=8\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=-4\end{matrix}\right.\)
|2x – 5| = 3
TH1: |2x – 5| = 2x – 5 khi 2x – 5 ≥ 0 ó 2x ≥ 5 ó x ≥ 5/2
Khi đó |2x – 5| = 3
=> 2x – 5 = 3 ó 2x = 8 ó x = 4 (TM)
TH2: |2x – 5| = - (2x – 5) khi 2x – 5 < 0 ó 2x < 5 ó x < 5/2
Khi đó |2x – 5| = 3
ð - (2x – 5) = 3 ó 2x = 2 ó x = 1 (TM)
Vậy phương trình có nghiệm là x = 4; x = 1
TH1:
2x+5=3
2x= 3-5
2x=-2
x=-1
TH2:
2x+3=-5
2x= -5-3
2x=-8
x= -4
\(\left|2x+5\right|=3\)
TH1 : \(\left|2x+5\right|=3\)
\(2x=3-5\)
\(2x=-2\)
\(x=-1\)
Th2 : \(\left|2x+5\right|=-3\)
\(2x=\left(-3\right)-5\)
\(2x=-8\)
\(x=-4\)
Vậy \(x=\left[{}\begin{matrix}-1\\-4\end{matrix}\right.\)