2x+2x+1+2x+2+2x+3=120
2x+2x.2+2x.4+2x.8=120
2x.(1+2+4+8)=120
2x.15=120
2x=120:15
2x=8
2x=23
x=3
Vậy x=3
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=120\)
\(\Rightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=120\)
\(\Rightarrow2^x\left(1+2+2^2+2^3\right)=120\)
\(\Rightarrow2^x.15=120\)
\(\Rightarrow2^x=8\)
\(\Rightarrow2^x=2^3\)
\(\Rightarrow x=3\)
Vậy x = 3
\(2^x+2^{x+1}+2^{x+2}+2^{x+3}=120\)
\(\Leftrightarrow2^x\cdot1+2^x\cdot2^1+2^x\cdot2^2+2^x\cdot2^3=120\)
\(\Leftrightarrow2^x\left(1+2^1+2^2+2^3\right)=120\)
\(\Leftrightarrow2^x\left(1+2+4+8\right)=120\)
\(\Leftrightarrow2^x\cdot15=120\)\(\Leftrightarrow2^x=8\)
\(\Leftrightarrow2^x=2^3\Leftrightarrow x=3\)
mấy bài này dễ làm ....anh em ra tay nhiều nhỉ