Question

(2x^2+16x^3+3x-4):(2x-1)

Answer 1

\(=\dfrac{16x^3-8x^2+10x^2-5x+8x-4}{2x-1}=8x^2+5x+4\)

Answer 2

(2x²+2x+16x³+3x-4):(2x-2)

=2x²:2x+16x³:2x+3x:2x-4:2x-2x²+16x³+3x-4

=x+8x²+1,5-2x-2x²+16x³+3x-4

=(x+3x-2x)+(8x²-2x²)+(1,5-4)+16x³

=2x+6x²-2,5+16x³

=16x³+6x²+2x-2,5