Question

(2x^2 -1). (x^3 +3x -1/2)

Answer 1

\(\left(2x^2-1\right)\left(x^3+3x-\dfrac{1}{2}\right)\)

\(=2x^2\left(x^3+3x-\dfrac{1}{2}\right)-1\left(x^3+3x-\dfrac{1}{2}\right)\)

\(=2x^5+6x^3-x^2-x^3+3x-\dfrac{1}{2}\)

\(=2x^5+5x^3-x^2+3x-\dfrac{1}{2}\)

Answer 2

(2x²-1).(x³+3x-1/2)

=2x⁵ + 6x³- x²- x³- 3x + 1/2

Answer 3

\(\left(2x^2-1\right).\left(x^3+3x-\dfrac{1}{2}\right)\)

= \(2x^5+6x^3-x^2-x^3-3x+\dfrac{1}{2}\)