\(2^x+1=8\)
\(2^x=8-1\)
\(2^x=7\)
\(\Rightarrow x\in\varnothing\)
Vậy x thuộc \(\varnothing\)
Đúng 0
Bình luận (5)
Ôn tập toán 7
Các câu hỏi tương tự
Tìm x
a) x-6/7 + x-7/8 + x-8/9 = x-9/10 + x-10/11+x-11/12
b) x+32/11 + x+23/12 = x+38/13 + x+27/14
c) | x-2| = 13
d) 3|x-2| + |4x-8| = |-2| - |1/3|
e) |3x-2|+5^-1 = 3 + | x- (2/3) |
f) | x+2 | + | x-2 | = 3
g) (2x-1)^2 - 5 = 20
i) (x+2)^2 = 1/2 - 1/3
k) (x-1)^3 = (x-1)
m) (x-1)^x+2 = (x-1)^2
n) (x+3)^y+1 = (2x-1)^y+1 vs y là 1 số tự nhiên .
1.Cho A=1/1.2+1/3.4+...+1/99.100
C/m :7/12<A<5/6
2.Tim x:
a.2/(x+2)(x+4)+4/(x+4)(x+8)+6/(x+8)(x+14)
b.x-10/30+x-14/43+x-5/95+x-148/8=0
Lam giup minh nhe
Minh dang can gap
(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16)=1
BÀI 1 - Tính
a (0,8)^5/(0,4)^6
b 8^10+4^10/8^4+4^11
BÀI 2 - Tìm x ϵ Z
a 2^x-1 = 16
b (x-1)^2 = 25
c (x-1)^x+2 = (x-1)^x+6
d (x+20)^100 + I y+4 I = 0
Tìm x
a) -3 ( 2/5x - 1/5) - x(x - 1/2) = 1/6 - x²
b) (2x - 1/2).2 + (1/2 + 1/3 +1/4): 1/8 = 1
c) 3| x -1/2| - 1 = 7
1)(x+7)(3x-1)=49-x^2
2)(2x+1)^2-(x-1)^2=0
3)(1-2x)^2-(x+3)^2+3(x+1)(1-x)=8
4)(x-3)^2-(x+3)^2=24
Giúp mk nha
Tìm x ϵ Z
\(\left(\frac{-3}{2}:\frac{3}{-1}\right).\left(\frac{-9}{2}\right)-\frac{1}{4}< \frac{x}{8}< \frac{-1}{2}.\frac{3}{4}:\frac{1}{8}+1\)
tìm x bết
a) 3,(5)+x=4,(2)
b) 1,1(8)-x=2,(1)
c) [x+2,(1)]:1,(2)=4,(8)
d) 4,(6):x=2,(3) * 0,0(4)
\(\frac{1^{x+1}}{2^{x+1}}=\frac{1}{8}\)
A= 4 x ( 3^2+1 ) x ( 3^4+1 ) x ( 3^8+1 ) x ( 3^16+1 ) và B= 3 ^32 -1