Question

2(x+1)²-2=0

Answer 1

`<=> 2(x+1)^2 = 2`

`-> (x+1)^2 = 1`

`->` \(\left[{}\begin{matrix}x+1=1\\x+1=-1\end{matrix}\right.\)

`->` \(\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)

Answer 2

\(2\left(x+1\right)^2=2\\ \left(x+1\right)^2=1\\ \left(x+1\right)^2-1=0\\ \left(x+1-1\right)\left(x+1+1\right)=0\\ \left[{}\begin{matrix}x=0\\x+2=0\end{matrix}\right.=>\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)