`2x-2-x^2+2x-1=0`
`<=> -x^2 +4x-3=0`
`<=> -(x^2-4x+3)=0`
`<=> -(x^2-x-3x+3)=0`
`<=> -[x(x-1) -3(x-1)]=0`
`<=>-(x-1)(x-3)=0`
\(\Leftrightarrow\left[{}\begin{matrix}-x+1=0\\x-3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}-x=-1\\x=3\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)
Vậy \(S=\left\{1;3\right\}\)
\(2x-2-x^2+2x-1=0\\ \Leftrightarrow x^2-4x+3=0\\ \Leftrightarrow\left(x-3\right)\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)
Vậy nghiệm của phương trình là S = \(\left\{1;3\right\}\).
