$(2x - \dfrac13)^5 = \dfrac{32}{243}$
$(2x - \dfrac13)^5 = \dfrac{2^5}{3^5}$
$(2x - \dfrac13)^5 = \left(\dfrac23\right)^5$
$2x - \dfrac13 = \dfrac23$
$2x = 1$
$x = \dfrac12$.
\(\dfrac{2x}{32}=1\)
\(\dfrac{2x}{32}=1\)
\(\dfrac{2x}{32}=1\)
Tìm x:
1) -3.(1-2x) - 4.(1+3x) = -5x + 5
2) 3.(2x - 5) - 6.(1 - 4x) = -3x + 7
3) (1 - 3x) - 2.(3x - 6) = -4x - 5
4) x.(4x - 3) - 2x.(2x - 1) = 5x - 7
5) 3x.(2x - 1) - 6x.(x + 2) = -3x + 4
6) (1 - 2x).3 - 4.(6x - 1) = 7x - 5
7) 6x - 3.(1 - 4x) - 5.(x + 1) = 2x + 7
8) 6.(1 - 3x) - 3.(2x + 5) = -10x + 7
9) 3x.(1 - 2x) + 6x^2 - 7x = 8.(1 - 2x) - 9
10) 2x.(1 + 3x) - 3x.(4 + 2x) = 3x - 4
1. Thực hiện phép tính:
a) 3\(^3\) . 9\(^{-1}\)
b) 25 . 5\(^{-1}\). 5\(^0\)
c) 3\(^2\). \(\frac{1}{243}\). 81\(^2\). 3\(^{-3}\)
d) 3\(^2\). 2\(^5\) . (\(\frac{3}{2}\) )\(^{-2}\)
tìm x
\(\dfrac{2x+1}{5}=\dfrac{3}{2x-1}\)
Tìm GTLN của biểu sau
A = - | x| D = 4 - |5x -2| - | 3y + 12|
B= 1 - | 2x - 5| E= 5 - 3 . ( 2x -1 )
C= | x - 3| - | 5 - x|
GIÚP MK NHA MAI NỘP BÀI
Bài 1: Thực hiện phép tính:
a) \(\left(\frac{3}{5}\right)^2-[\frac{1}{3}:3-\sqrt{16}.\left(\frac{1}{2}\right)^2]-\left(10\times12-2014\right)^0\)
b)\(|-\frac{100}{123}|:\left(\frac{3}{4}+\frac{7}{12}\right)+\frac{23}{123}:\left(\frac{9}{5}-\frac{7}{15}\right)\)
c) \(\frac{\left(-5\right)^{32}\times20^{43}}{\left(-8\right)^{29}\times125^{25}}\)
Bài 2: Tìm x biết
a)\(\frac{2}{3}-\left(\frac{3}{4}-x\right)=\sqrt{\frac{1}{9}}\)
b) \(\left(\frac{1}{2}-x\right)^2=\left(-2\right)^2\)
c) \(|3x+\frac{1}{2}|-\frac{2}{3}=1\)
d) \(3^{2x+1}=81\)
tìm x biết: \(\dfrac{2x-1}{3}=\dfrac{-5}{0,6}\)
a) \(\dfrac{2}{3}\)x + 0,25 = \(-\dfrac{5}{8}\) - \(\left(\dfrac{1}{2}-\dfrac{3}{4}x\right)\)
b) ( \(9x^2\) -1 ) . ( 2x + 3 ) = 0
c) \(\left|2x-\dfrac{1}{3}\right|-\dfrac{3}{4}=\left|-\dfrac{5}{6}\right|\)
d) \(\left(0,75-\dfrac{5}{6}x\right)^3\) = \(-\dfrac{27}{64}\)
e) \(\left(\dfrac{2}{5}x-\dfrac{1}{2}\right)^2=\dfrac{9}{16}\)
f) \(\dfrac{2x-3}{3}=\dfrac{3x+2}{7}\)
h)\(\left(\dfrac{2}{3}\right)^{2x+1}\) = \(\left(\dfrac{8}{27}\right)^3\)
i) \(2.5^{3x}+5^{3x+2}=3375\)
bài 2 giúp đi mọi người
a,\(\frac{-2}{5}+x=\left(\frac{-1}{3}\right)^2+\frac{2}{3}\)
b,\(\frac{3}{5}-2x=\left(\frac{-3}{5}\right)^2+:\frac{9}{25}\)
c,\(\left|2x-1\right|=\frac{1}{2}-\frac{-2}{3}\)
d,\(\left(x-\frac{3}{4}\right).\frac{1}{2}=\left(\frac{-1}{2}\right)^2\)
