ĐKXĐ: \(x^2+2x-1\ge0\)
\(x^2+2x-1+2\left(x-1\right)\sqrt{x^2+2x-1}+\left(x-1\right)^2-\left(x+1\right)^2=0\)
\(\Leftrightarrow\left(\sqrt{x^2+2x-1}+x-1\right)^2-\left(x+1\right)^2=0\)
\(\Leftrightarrow\left(\sqrt{x^2+2x-1}+2x\right)\left(\sqrt{x^2+2x-1}-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}\sqrt{x^2+2x-1}+2x=0\\\sqrt{x^2+2x-1}-2=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=-1-\sqrt{6}\\x=-1+\sqrt{6}\end{matrix}\right.\)
Đúng 0
Bình luận (0)
