Ta có: \(2011+2010\cdot\left(-4\cdot5^2+11\cdot3^2\right)^{2009}\)
\(=2011+2010\cdot\left(-4\cdot25+11\cdot9\right)^{2009}\)
\(=2011+2010\cdot\left(-100+99\right)^{2009}\)
\(=2011+2010\cdot\left(-1\right)^{2009}\)
\(=2011+2010\cdot\left(-1\right)\)
\(=2011+\left(-2010\right)\)
\(=2011-2010=1\)
(1+1/1*3)*(1+1/2*4)*(1/3*5)*...*(1/99*101)
giúp tớ nữa nhé Nguyễn Lê Phước Thịnh kaka :)))