ĐK: \(x\ge3\)
\(x-7\sqrt{x-3}-9=0\)
\(\Leftrightarrow x-3-7\sqrt{x-3}-6=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x-3}=\dfrac{7+\sqrt{73}}{2}\\\sqrt{x-3}=\dfrac{7-\sqrt{73}}{2}\left(l\right)\end{matrix}\right.\)
\(\Leftrightarrow x-3=\dfrac{61+7\sqrt{73}}{2}\)
\(\Leftrightarrow x=\dfrac{67+7\sqrt{73}}{2}\left(tm\right)\)