Giải:
Bài 1:
a) \(\left(x-\dfrac{1}{2}\right)^2=x^2-x+\dfrac{1}{4}\)
b) \(\left(2x-3y\right)^2=4x^2-12xy+9y^2\)
c) \(99^2=\left(100-1\right)^2=100^2-200+1^2=10000-200+1=9801\)
Bài 2:
a) \(\left(x+1\right)\left(x-1\right)=x^2-1^2=x^2-1\)
b) \(\left(x-2y\right)\left(x+2y\right)=x^2-\left(2y\right)^2=x^2-4y^2\)
c) \(56.64=\left(60-4\right)\left(60+4\right)=60^2-4^2=3600-16=3584\)
Chúc bạn học tốt!
\(\left(x-\dfrac{1}{2}\right)^2=x^2-x+\dfrac{1}{4}\)
\(\left(2x-3y\right)^2=4x^2-12xy+9y^2\)
\(99^2=\left(100-1\right)^2=100^2-200+1=10000-199=9801\)
\(\left(x+1\right)\left(x-1\right)=x^2-1\)
\(\left(x-2y\right)\left(x+2y\right)=x^2-4y^2\)
\(56.54=\left(55+1\right)\left(55-1\right)=55^2-1=3024\)
1.
a)\(\left(x-\dfrac{1}{2}\right)^2\)
=\(x^2-2.x.\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2\)
=\(x^2-x+\dfrac{1}{4}\)
b)\(\left(2x-3y\right)^2\)
=\(\left(2x\right)^2-2.2x.3y+\left(3y\right)^2\)
=\(4x^2-12xy+9y^2\)
c)992=(100-1)2=1002-2.100.1+12=10000-200+1=8000
2.
a)(x-1).(x+1)=x2-12
b)(x-2y).(x+2y)=x2-2y2
c)Hình như sai đề.