1) (12x-5).(4x-1)+(3x-7).(1-16x)=81
48x\(^2\)-12x-20x+5+3x-48x\(^2 \) -7+112x=81
83x+5-7=81
83x=83
x=1
Vậy x=1
2)Ta có \(\widehat{A}+\widehat{D}=180^o\)(Hai góc nằm trong vị trí trong cùng phía)(1)
Theo đề ra ta có: \(\widehat{A}-\widehat{D}=20^o\)(2)
Từ (1) và(2) ta có:
\(\widehat{A}+\widehat{D}-(\widehat{A}-\widehat{D})=180^o-20^o=160^o\)
\(\widehat{A}+\widehat{D}-\widehat{A}+\widehat{D}=2\widehat{D}=160^o\)
\(\Rightarrow \widehat{D}=80^o\)
Thay \(\widehat{D}=80^o\) vào (1) ta có:
\(\widehat{A}+80^o=180^o\)
\(\Rightarrow \widehat{A}=180^o-80^o=100^o\)
\(\Rightarrow \)G.A=\(100^o\);\(G.D=80^o\)
Vậy cây C) đúng