Bài 1:
a: \(\left(\dfrac{1}{6}\right)^7=\left(\dfrac{1}{2}\right)^7\cdot\left(\dfrac{1}{3}\right)^7=\left(\dfrac{1}{2}\right)^7\cdot\left(\dfrac{1}{3}\right)^5\cdot\left(\dfrac{1}{3}\right)^2\)
\(\left(\dfrac{1}{12}\right)^5=\left(\dfrac{1}{2}\right)^{10}\cdot\left(\dfrac{1}{3}\right)^5=\left(\dfrac{1}{2}\right)^7\cdot\left(\dfrac{1}{3}\right)^5\cdot\dfrac{1}{8}\)
mà 1/9<1/8
nên (1/6)^7<(1/12)^5
b: \(\left(-\dfrac{1}{81}\right)^{100}=\left(\dfrac{1}{3}\right)^{400}\)
\(\left(-\dfrac{1}{3}\right)^{500}=\left(\dfrac{1}{3}\right)^{500}\)
=>\(\left(-\dfrac{1}{81}\right)^{100}< \left(-\dfrac{1}{3}\right)^{500}\)