1)Tính m hh à bạn?
Cho hh t/d vs H2SO4 dư chỉ có Fe p/ứ
nH2=2,24/22,4=0,1(mol)
Fe+H2SO4--->FeSO4+H2
0,1_________________0,1
mFe=0,1.56=5,6(g)
Cho hh t/d vs H2SO4 đặc
nSO2=5,6/22,4=0,25(mol)
2Fe+6H2SO4--->Fe2(SO4)3+3SO2+6H2O
0,1_______________________0,15
Cu+2H2SO4--->CuSO4+SO2+2H2O(1)
Theo pt(1):nCu=nSO2(1)=0,25-0,15=0,1(mol)
=>mCu=0,1.64=6,4(g)
=>mhh=6,4+5,6=12(g)