Câu 1:
Vsau = 800 + 200= 1000ml = 1 lít
\(n_{NaOH}=0,2.0,4=0,1\left(mol\right)\)
\(\Rightarrow CM_{NaOH}=0,1M\)
Câu 2:
\(n_{CuSO4}=0,2.0,4=0,08\left(mol\right)\)
\(V_{dd\left(CuSO4\right)}=\frac{0,08}{0,6}=0,133\left(l\right)\)
\(V_{H2O}=0,4-0,133=0,267\left(l\right)\)