B) \(\left|3x-6\right|+\left|x+1\right|=x\)
\(\Leftrightarrow\left|3x-6\right|+\left|x+1\right|-x=0\)
TH1: \(x\le-1\)
6-3x-x-1-x=0\(\Leftrightarrow\) x=\(-1\) (thỏa mãn)
TH2: \(-1< x\le2\)
6-3x +x+1-x=0\(\Leftrightarrow\) x= \(\dfrac{7}{3}\)( thỏa mãn)
TH3 : x>2
3x-6+x+1-x=0\(\Leftrightarrow x=\dfrac{5}{3}\) (loại)