\(A=\left(-2a+3b-4c\right)-\left(-2a-3b-4c\right)\)
=\(-2a+3b-4c+2a+3b+4c\)
\(=\left(2a-2a\right)+\left(3b+3b\right)+\left(4c-4c\right)\)
\(=6b\)
Thay \(a=2012\) \(b=-1\)\(c=2013\)vào A ta đc
A=\(\left(-2.2012+3.-1-4.2013\right)-\left(-2.2012-3.-1-4.2013\right)\)
\(=-2012.2+-3-4.2013+2.2012-3+4.2013\)
=\(\left(2012.2-2.2012\right)+\left(-3-3\right)+\left(4.2013-4.2013\right)\)
\(=-6\)