ĐKXĐ: x∉{0;2}
\(\frac{17}{3x}-\frac23=\frac{1}{2-x}\)
=>\(\frac{17-2x}{3x}=\frac{1}{2-x}\)
=>(2-x)(17-2x)=3x
=>(x-2)(2x-17)=3x
=>\(2x^2-17x-4x+34-3x=0\)
=>\(2x^2-24x+34=0\)
=>\(x^2-12x+17=0\)
=>\(x^2-12x+36=19\)
=>\(\left(x-6\right)^2=19\)
=>\(\left[\begin{array}{l}x-6=\sqrt{19}\\ x-6=-\sqrt{19}\end{array}\right.\Rightarrow\left[\begin{array}{l}x=6+\sqrt{19}\left(nhận\right)\\ x=6-\sqrt{19}\left(nhận\right)\end{array}\right.\)
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