Question

16x^2-8x+1=4(x+3)(4x-1)

Answer 1

\(16x^2-8x+1=4\left(x+3\right)\left(4x-1\right)\)

<=>\(\left(4x-1\right)^2=4\left(x+3\right)\left(4x-1\right)\)

<=>\(4x-1=4\left(x+3\right)\)

<=>\(4x-1=4x+12\)

<=> \(0x=13\) => Phương trình vô nghiệm

=> S = {∅}

Answer 2

16x² - 8x + 1 = 4(x + 3)(4x -1)

<=> (4x)² - 8x + 1 = (4x + 12)(4x -1)

<=> (4x - 1)² = (4x + 12)(4x -1)

<=> (4x - 1)² - (4x + 12)(4x -1) = 0

<=> (4x - 1)(4x - 1 - 4x - 12) = 0

<=> -13(4x - 1) = 0

<=> 4x - 1 = 0

<=> \(x=\frac{1}{4}\)

Mình không chắc, sai gì thì thông cảm hey~

Answer 3

16x² - 8x + 1 = 4(x + 3)(4x - 1)

\(\Leftrightarrow\) 16x² - 8x + 1 = 16x² + 44x − 12

\(\Leftrightarrow\) (16x² - 16x²) + (- 8x - 44x) = - 12 - 1

\(\Leftrightarrow\) - 52x = - 13

\(\Leftrightarrow\) x = \(\frac{-13}{-52}\)

\(\Leftrightarrow\) x = \(\frac{1}{4}\)

Vậy S = {\(\frac{1}{4}\)}

Chúc bạn học tốt!