\(\left(\dfrac{1}{3}\right)^x=\left(\dfrac{1}{3}\right)^2\Rightarrow x=2\)
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Đại số lớp 7
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Tìm x:2/3a, x/2=-8/-x
b, x:1/8=1/8:x
c,2/-x=x/-18
d,(x-1)^2/3=24/3
Tìm x, biết:
a/ \(\frac{5}{6}x-\frac{3}{8}x-10=12\)
b/ (/x/-1/8) . \(\left(-\frac{1}{8}\right)^5=\left(-\frac{1}{8}\right)^7\)
c/ \(3^x+3^{x+1}+3^{x+2}=117\)
|x−1|+|x−3|+|x−5|+|x−7|=8|x−1|+|x−3|+|x−5|+|x−7|=8
nhanh nha
a) -3/20 - 2/5 b)-1/2x-5/3=1/2 c) 3/7 - 2/3x=-5/3 d) 3/8.x-5/2=1/2.x-1/3
Tìm x biết
a) 3(1-4x).(x-1)+4(3x-2).(x+3)=-27
b) (x+3).(x2-3+9)-.(x-1).(x+1)=27
c) 2x2+3(x-1).(x+1)=5x.(x+1)
d) 8(x-1).(x+5)-(x+2).(x+5)=3(x-1).(x+2)
Tìm x thỏa mãn: 8(x-\(\dfrac{1}{2}\))x+3=(x-\(\dfrac{1}{2}\))
Tìm x:
\(\dfrac{2}{\left(x-1\right)\left(x-3\right)}+\dfrac{5}{\left(x-3\right)\left(x-8\right)}+\dfrac{12}{\left(x-8\right)\left(x-20\right)}-\dfrac{1}{x-20}=\dfrac{-3}{4}\)
Tìm x
1) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^6\) 2) \(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{8}\right)^{36}\) 3) \(\left(\dfrac{1}{81}\right)^x=\left(\dfrac{1}{27}\right)^4\)
4) \(\left(\dfrac{4}{9}\right)^x=\left(\dfrac{8}{27}\right)^{10}\) 5) \(2^x=4^5.4^3\) help me !!!!
Tìm x biết:
A, -5(x-7)-7(x+3)=8
B, 6(x+1)-5(x-2)=8
C, 3x+4x+5x+6x=30
D, (x+1)+(x+2)+(x+3)+...+(x+10)=144